Random Resource Fetcher with Content-Type Detection

This function fetches a resource from a given URL and returns JSON, HTML, or plain text based on the response's Content-Type.

Technology Stack : requests, BeautifulSoup

Code Type : Function

Code Difficulty : Intermediate

                
                    
import requests
import random

def fetch_random_resource(url):
    response = requests.get(url)
    content_type = response.headers.get('Content-Type')
    if 'json' in content_type:
        return response.json()
    elif 'html' in content_type:
        from bs4 import BeautifulSoup
        return BeautifulSoup(response.content, 'html.parser').text
    else:
        return response.text

# JSON response