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This function takes a string argument and returns a dictionary containing the count of each English letter (case insensitive) in the string.
Technology Stack : collections, string
Code Type : Function
Code Difficulty : Intermediate
def a_to_z_counter(text):
"""
计算给定文本中每个字母(忽略大小写)的出现次数,并返回一个包含字母及其出现次数的字典。
"""
from collections import Counter
from string import ascii_lowercase
# 将文本转换为小写并计算每个字母的出现次数
lower_text = text.lower()
letter_counts = Counter(lower_text)
# 过滤掉不在字母表中的字符,只保留26个英文字母
filtered_counts = {letter: count for letter, count in letter_counts.items() if letter in ascii_lowercase}
return filtered_counts
# 代码示例
text = "Hello, World! This is a simple test to count letters from a to z."
result = a_to_z_counter(text)
print(result)